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四川高职高考复习题_四川职高试卷

作者:四川职业学校 来源:招生指南网 更新时间:2024-03-25 02:46 热度:0

四川高职高考复习题

随着高中阶段的结束,许多学生开始向往大学和职业学校,因此高考成为他们实现这些梦想的重要方式。在四川省,高职高考也是许多学生的选择。以下是一些复习题,帮助学生准备四川高职高考。

四川高职高考复习题_四川职高试卷

数学

1.已知函数$f()=3^2-2+1$和函数$g()=\frac{2}{-1}$,则$g(f(2))=$?

2.若$\sin \alpha=0.6$,则$\cos 2\alpha=$?

3.如图,$ABED$ 为正方形,$\triangle BCD$ 为等腰直角三角形,$BC=CD=2$,$BE=3$,则 $\triangle ABE$ 的面积为( )

四川高职高考复习题_四川职高试卷

英语

1.单项选择:— Why didn't you go to the meeting yesterday? — I _____ it. A. forgot B. had forgotten C. would forget D. have forgotten

2. 完型填空:I was on a bus last night. An old woman got on and I saw that she looked very poor. She was carrying a bag, and it looked heavy. So I stood up and gave her my seat. She _____ down and thanked me. Then she opened her bag and took out an apple. She gave it to me and s#d, "Thank you very much." I didn't want the apple, but I didn't want to _____ her, so I took it.

3. 阅读理解:Astronauts have to be in ecellent physical and mental condition. They must have good eyesight and be no taller than 6 feet 4 inches tall. They have to be able to swim, because if their spacecraft lands in the water, they will need to be able to get out of it. They must also be able to work for long hours in small spaces with other people. Finally, they must be able to speak and write well, because they will be giving reports from space and helping to write tetbooks. According to the passage, what are some of the requirements to become an astronaut?

四川高职高考复习题_四川职高试卷

物理

1.一面光滑的平板玻璃,厚度为$d$,折射率为$n$,放在空气中,一束入射光垂直地射到玻璃板上,若反射光和折射光都垂直于玻璃板,则$d$应等于( )

A. $\frac{\lambda}{4n}$

B. $\frac{\lambda}{4}$

C. $\frac{\lambda}{2n}$

D. $\frac{\lambda}{2}$

2.一个电容器的电容为$C$,充电电压为$U_0$,在电容器两端加上一个相位差为$\frac{\pi}{2}$的正弦交流电源,则通过电容器的电流幅值为( )

A. $\frac{U_0}{C}$

B. $\frac{U_0}{\sqrt{2}C}$

C. $\frac{U_0}{2C}$

D. $\frac{U_0}{2\sqrt{2}C}$

3.如图所示,一根长为$l$的均匀细杆,质量为$m$,靠近杆的一端铅垂挂一质量为$M$的物体,杆与竖直方向的夹角为$\theta$,则此杆的转动惯量为( )

A. $\frac{1}{3}m(\frac{l}{2})^2$

B. $\frac{1}{3}m(\frac{l}{2}\cos \theta)^2$

C. $\frac{1}{3}m(\frac{l}{2}\sin \theta)^2$

D. $\frac{1}{3}m(\frac{l}{2})^2+\frac{1}{12}m l^2\sin^2\theta$

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